The reaction of 4-methylcyclohexyl halide wit | vedclass

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(D) The $S_N2$ mechanism involves a backside attack by the nucleophile $(OH^-)$ on the carbon atom bonded to the leaving group (halide).This results i

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(D) The $S_N2$ mechanism involves a backside attack by the nucleophile $(OH^-)$ on the carbon atom bonded to the leaving group (halide).This results in the inversion of configuration at the chiral center.If the starting material is a $cis-4-methylcyclohexyl$ halide,the $OH^-$ will attack from the opposite side of the halide,leading to the $trans-4-methylcyclohexanol$ product.Conversely,if the starting material is a $trans-4-methylcyclohexyl$ halide,the product will be the $cis-4-methylcyclohexanol$.Since the specific stereochemistry of the starting halide is not provided in the prompt,and the options refer to general stereochemical outcomes of $S_N2$ reactions on substituted cyclohexanes,the inversion of configuration is the key principle.Given the options provided,the reaction proceeds with inversion of configuration.

The reaction of $4-methylcyclohexyl$ halide with $OH^-$ via the $S_N2$ mechanism produces $A$. Identify $A$.

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